i. Motion Resistive Force
The force required to overcome the frictional force is calculated as follows:
Normal Force = (mass x g) cos theta
Force required = 0.0055 x Normal Force = 2.548 N
But in this case we have to overcome the (mass x g) component in the inclined plane direction therefore we have to add [(mass x g) sin theta] to (Force required). The total required force in this case:
(0.0055 x 470 cos 10) + (48 x 9.8) sin 10 = 84.232 N (total resisting force)
ii. Torque Calculation
Going back to torque equation now we can calculate the torque. In this case we will use the required force equal to the resistive force because the acceleration is assumed zero (no acceleration required in the inclined plane scenario).
Torque = Force x raduis = 84.232 x 0.3302 = 27.81 N
Total Torque = 2 x 27.81 = 55.627 N
iii. Power Calculation
Going back to torque equation now we can calculate the torque.
Power = Torque x rotational speed = 55.627 x 6.73 = 374.365 W
1 comment:
Well said.
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